2(x^2+8)=16

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Solution for 2(x^2+8)=16 equation: 



2(x^2+8)=16

We move all terms to the left:

2(x^2+8)-(16)=0

We multiply parentheses

2x^2+16-16=0

We add all the numbers together, and all the variables

2x^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$

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